Chapter 1

A downhill skier crosses the finishing line at a speed of 30 m s1 and immediately starts to decelerate at 10 m s ̃2. There is a barrier 50 metres beyond the finishing line. (a) Find an expression for the skier’s speed when she is s metres beyond the finishing line. (b) How fast is she travelling when she is 40 metres beyond the finishing line? (c) How far short of the barrier does she come to a stop? (d) Display an (s, v) graph to illustrate the motion.

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Title: Downhill Descent: The Braking Skier’s Journey Introduction: Embarking on a thrilling downhill descent, a skier accelerates across the finishing line with a speed of 30 m/s. However, the journey doesn’t end there; an immediate deceleration ensues, dictated by the skier’s effort to safely navigate the terrain. This numerical exploration unveils the dynamics of the … Read more

An ocean liner leaves the harbour entrance travelling at 3 m s1, and accelerates at 0.04 m s2 until it reaches its cruising speed of 15 m s1. (a) How far does it travel in accelerating to its cruising speed? (b) How long does it take to travel 2 km from the harbour entrance?

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Title: Seafaring Acceleration: The Ocean Liner’s Voyage Introduction: Embarking on a maritime journey, an ocean liner sets sail from the harbour entrance with an initial velocity of 3 m/s. The vessel undergoes a calculated acceleration, propelling it to a steady cruising speed of 15 m/s. This numerical exploration delves into the liner’s acceleration phase, unveiling … Read more

A train travelling at 55 m s1 has to reduce speed to 35 ms to pass through a junction. If the deceleration is not to exceed 0.6 m s2, how far ahead of the junction should the train begin to slow down?

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Title: Strategic Deceleration: Train at the Junction Introduction: Navigating the intricacies of railway dynamics, this numerical exploration examines a scenario where a train, hurtling at 55 m/s, strategically adjusts its velocity to 35 m/s for a safe passage through a junction. The primary focus is on determining the critical distance at which the train must … Read more

A cyclist riding at 5 m s1 starts to accelerate, and 200 metres later she is riding at 7 m s’. Find her acceleration, assumed constant.

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Title: Cycling Acceleration Challenge Introduction: Embarking on a journey of acceleration, our cyclist’s pedal-powered adventure unfolds as she transitions from a cruising speed of 5 m/s to a sprightly 7 m/s. The crux of this numerical exploration lies in uncovering the acceleration experienced by the cyclist during this dynamic shift. Scenario Overview: Picture a cyclist … Read more

A motor-scooter moves from rest with acceleration 0.1 m s2. Find an expression for its speed, v m s1, after it has gone s metres. Illustrate your answer by sketching an (s, v) graph.

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Title: Acceleration Unveiled: Motor-Scooter Odyssey Introduction: Embarking on a journey from a state of rest, a motor-scooter gradually unfolds its accelerating prowess, attaining a velocity that intricately corresponds to the distance covered. This numerical exploration seeks to unveil the relationship between speed and distance for a motor-scooter accelerating at a consistent rate. Scenario Overview: Imagine … Read more

A train goes into a tunnel at 20 m s1 and emerges from it at 55 m s1. The tunnel is 1500 m long. Assuming constant acceleration, find how long the train is in the tunnel for, and the acceleration of the train.

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Title: Tunnel Odyssey: Unveiling Train Acceleration Introduction: Embarking on a tunnel journey, a train gracefully transitions from one speed to another, threading through the tunnel’s mysterious expanse. This numerical exploration unveils the secrets of the train’s acceleration, shedding light on the time spent within the tunnel and the acceleration it undergoes. Scenario Overview: Picture a … Read more

(a) u=9,a=4,s=5, find v (c) u=17, v = 11, s = 56, find a (e) v = 20, a = 1,1 = 6, find s (g) u = 18, v=12, s = 210, find t (i) u=20,s=110, t = 5, find v (k) u=24, v = 10, a = -0.7, find t (m) v = 27, s = 40, a = -41⁄2, find t (b) u = 10, v = 14, a = 3, find s (d) u=14, a = -2, t = 5, find s (f) u=10,s=65, t = 5, find a (j) (h) u 9,a=4, s = 35, find t s=93, v = 42, t = 2, find a (1) s=35, v=12, a = 2, find u (n) a = 7,s=100, v-u 20, find u

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Introduction: solve these numericals by applying general basic equations which i have described below Douglas Quadling Mechanics1 Exercise1C Q1