Exercise 1B

A balloon at a height of 300 m is descending at 10 ms-1 and decelerating at a rate of 0.4 ms-2 How long will it take for the balloon to stop descending, and what will its height be then?

by
A balloon at a height of 300 m is descending at 10 ms and decelerating at a rate of 0.4 ms 2.

Title: Soaring Heights: The Balloon’s Descent: A balloon at a height of 300 m is descending at 10 ms and decelerating at a rate of 0.4 ms-2 ….. Introduction: Embarking on an atmospheric descent, this numerical voyage navigates the trajectory of a balloon gracefully descending from the lofty heights. Decelerating at a controlled rate, the … Read more

A train is travelling at 80 m s1 when the driver applies the brakes, producing a deceleration of 2 ms 2 for 30 seconds. How fast is the train then travelling, and how far does it travel while the brakes are on?

by

3 October 2023 by alevelmechanics1.com Title: Braking Momentum: Deceleration Chronicles Introduction: Embarking on a journey of braking dynamics, this numerical exploration delves into the scenario of a train hurtling at 80 m/s. When the driver commands a forceful deceleration, the train’s journey transforms, unraveling the intricacies of speed reduction and the spatial displacement during braking. Scenario Overview: … Read more

Starting from rest, an aircraft accelerates to its take-off speed of 60 m s1 in a distance of 900 metres. Assuming constant acceleration, find how long the take-off run lasts. Hence calculate the acceleration.

by

3 October 2023 by alevelmechanics1.com Title: Soaring to Take-Off: Aircraft Acceleration Odyssey Introduction: Embarking on the thrilling journey of take-off, this numerical exploration unveils the acceleration escapade of an aircraft. Starting from a standstill, the aircraft accelerates relentlessly, aiming to attain the coveted take-off speed of 60 m/s. The focus lies on deciphering the temporal dynamics of … Read more

A long-jumper takes a run of 30 metres to accelerate to a speed of 10 m s1 from a standing start. Find the time he takes to reach this speed, and hence calculate his acceleration. Illustrate his run-up with a velocity-time graph.

by

3 October 2023 by alevelmechanics1.com Title: Leap into Motion: Long-Jumper’s Acceleration Adventure Introduction: Embarking on the runway of anticipation, a long-jumper, poised for a remarkable leap, undertakes a run-up to accelerate from a standstill to a speed of 10 m/s. This numerical exploration seeks to unravel the temporal intricacies of the acceleration journey, calculating the time it … Read more

A train travelling at 20 m s1 starts to accelerate with constant acceleration. It covers the next kilometre in 25 seconds. Use the equation s = ut+at2 to calculate the acceleration. Find also how fast the train is moving at the end of this time. Illustrate the motion of the train with a velocity-time graph. How long does the train take to cover the first half kilometre?

by

3 October 2023 by alevelmechanics1.com Title: Journey Unleashed: Acceleration Chronicles of a Train Introduction: In the rhythmic cadence of its journey, a train initially cruising at 20 m/s decides to embark on an acceleration odyssey. This numerical exploration navigates through the acceleration chronicles, uncovering the train’s acceleration and its velocity at a specific juncture. The interplay of … Read more

A marathon competitor running at 5 m s1 puts on a sprint when she is 100 metres from the finish, and covers this distance in 16 seconds. Assuming that her acceleration is constant, use the equation s= = (u+v)t to find how fast she is running as she crosses the finishing line.

by

3 October 2023 by alevelmechanics1.com Title: Sprint to Glory: Marathoner’s Accelerated Finish Introduction: In the final stretch of a marathon, a competitor, propelled by a surge of determination, ignites a sprint just 100 meters from the finish line. This numerical exploration unveils the dynamics of her accelerated finish, delving into the realm of constant acceleration. By harnessing … Read more

A police car accelerates from 15 m s to 35 ms in 5 seconds. The acceleration is constant. Illustrate this with a velocity-time graph. Use the equation v=u+ at to calculate the acceleration. Find also the distance travelled by the car in that time.

by

3 October 2023 by alevelmechanics1.com Title: Pursuit in Motion: Police Car Acceleration Analysis Introduction: In the realm of law enforcement, a police car embarks on a rapid acceleration, surging from 15 m/s to 35 m/s in a mere 5 seconds. This numerical exploration unravels the dynamics of the police car’s acceleration through the lens of a velocity-time … Read more